середу, 13 грудня 2017 р.

Generator of energy on nonlinear inductance

OLD "GRABS"
material with skif.biz (or what the author hid)

A device with an efficiency of more than 1 is designed and assembled. It works in a self-sustaining mode, while allocating an enormous amount of energy that goes to the glow of the incandescent lamp. ........ Valery. free-energy@list.ru

At time t1:
The current from the capacitance C1 charged in advance flows through L1-L2-L3, and the switch S1 is closed. In this case, S2 is open: Since L1 and L2 are in phase
(the accumulation of energy in L1 and L2 does not occur, since their magnetic fields compensate each other), then the accumulation of energy occurs in the coil L3

At time t2:
The key S1 is opened and the key S2 is closed. In this case, there is an EMF in the coils L1 and L3 (As S2 turns out to be closed). The coils L1 and L3 turn on in phase (in the antiphase switching on the EMF is subtracted, and in in-phase is added)

Since the current in the coils is the same, we assume that the emf obtained at time t2 is twice as large as the energy expended at the time t1.

In this description, one coil cycle is shown. The control circuit provides a repetition of the process described above. The feedback loop returns some of the received power to the circuit input for the next operating cycles.

The resulting power gain is consumed by R-loads.


If you dig, you can find another solution, for example from Vadim Guk (DELAMORTO)


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Consider how the schema and its variants may look.

Unfortunately, it was the author's algorithm that did not lead to the indicated results. The shortening of the middle winding all one works to counter the field. The winding included in the antiphase must be eliminated, the variant of such solution is shown in the figure below with the master generator or on the trigger winding according to the J.Bedini variant.



So the coils are wound in layers, first symmetrically on the core L1 and L2 connected "in series", L3 is wound symmetrically on L2, but L3 is in series with L2.
  On the ferrite core, I recommend making a cutout on one side, there will always be a Bloch zone on the opposite side of the cut. If everything is done correctly, then the total inductance L = (L1 + L2) on the ring will be L T = 2 (L1 + L2), and not L T = (L 1 + L 2 + 2M).

The main thing in this circuit is the correct winding of the inductor. When current is excited in the circuit, the total field is accumulated by all three windings (1 + 2 + 3). After the excitation is turned off, the field is discharged through two coils (1 + 2), the total resistance (Ohm) of the two coils is less than the sum of the three coils, as during excitation. The movement of the magnetic flux does not cause interference. The current in the windings has the same spin excitation - generation. It is possible that his shot will increase in the direction of increase. Therefore, the discharge in the energy potential must be higher.

PS
In reality, you can freely remove some of the circuit elements, clarify the damper-sniper protection circuit of transistor Q2. The main thing is the correct winding and the corresponding core.

Refined scheme for half-bridge excitation.


The graph of the current strength taken from the resistor R-0.1 Ohm, which is installed from the output terminal of the winding L2, to the connection of the diode D3 and the beginning of the winding L3. DC supply voltage 11.8V.


*****

Glory to Ukraine! Glory to heroes!
Serge Rakarsky (Kyiv, Ukraine)



1 коментар:

henriquejne сказав...

Ótimo trabalho rico em detalhes, muito obrigado por postar...